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4.9t^2+330t-2310=0
a = 4.9; b = 330; c = -2310;
Δ = b2-4ac
Δ = 3302-4·4.9·(-2310)
Δ = 154176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{154176}=\sqrt{64*2409}=\sqrt{64}*\sqrt{2409}=8\sqrt{2409}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(330)-8\sqrt{2409}}{2*4.9}=\frac{-330-8\sqrt{2409}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(330)+8\sqrt{2409}}{2*4.9}=\frac{-330+8\sqrt{2409}}{9.8} $
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